In a voltmeter there are 20 divisions between the ‘0’ mark and 0.5 V mark. Calculate its least count.

Answer :

The minimum potential difference measured

by a voltmeter between the two given

terminals is called the least count of that voltmeter.

Two given marks of the \(voltmeters = 0 and 0.5 V\)

\(Potential difference = 0.5 – 0 = 0.5V\)

\(No. of divisions between these two marks = 20\)
\(\implies frac{0.5}{20}\)
\(\implies least count = 0.024\)