Q) The unit place digit of HCF of \(2^2 * 3^2 *5^3 * 7 , 2^3 * 3^3 * 5^2 * 7^2 * and 3 * 5 * 7 * 11\) is
  • 1) 70
  • 2) 105
  • 3) 175
  • 4) 225


Answer : Option 2

HCF = product of lowest powers of common factors
= 3 * 5 * 7
= 105

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