Q) If P = HCF (100 , 190) and q = LCM (100 , 190); then \(p^2q^2\) is:
  • 1) \(3.61 * 10^5\)
  • 2) \(3.61 * 10^3\)
  • 3) \(3.61 * 10^6\)
  • 4) \(3.61 * 10^8\)


Answer : Option 4

\(pq = (HCF)(LCM) = product of given numbers.\)
\(\implies\) \(pq = 190 * 100 = 19000\)
\(\implies\) \(p^2q^2\) = \( 361 * 10^6\) = \(3.61 * 10^8)

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