# Q) If P = HCF (100 , 190) and q = LCM (100 , 190); then $$p^2q^2$$ is: 1) $$3.61 * 10^5$$ 2) $$3.61 * 10^3$$ 3) $$3.61 * 10^6$$ 4) $$3.61 * 10^8$$

$$pq = (HCF)(LCM) = product of given numbers.$$
$$\implies$$ $$pq = 190 * 100 = 19000$$
$$\implies$$ $$p^2q^2$$ = $$361 * 10^6$$ = \(3.61 * 10^8)