Q.3 Write each of the following as decimals:

(a) Seven-tenths

(b) Two tens and nine-tenths

(c) Fourteen point six

(d) One hundred and two ones

(e) Six hundred point eight

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Answer :

(a) \(\frac{7}{10} \) = 0.7

(b) 20 + \(\frac{9}{10} \) = 20 . 9

(c) 14.6

(d) 100 + 2 = 102

(e) 600.8

Q.5 Write each of the following as decimals:

(a) \(\frac{5}{10} \)

(b) 3 + \(\frac{7}{10} \)

(c) 200 + 60 + 5 + \(\frac{1}{10} \)

(d) 70 +\(\frac{8}{10} \)

(e) \(\frac{88}{10} \)

(f) \(4\frac{2}{10} \)

(g) \(\frac{3}{2} \)

(h) \(\frac{2}{5} \)

(i) \(\frac{12}{5} \)

(j) \(3\frac{3}{5} \)

(k) \(4\frac{1}{2} \)

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Answer :

(a) \(\frac{5}{10} \) = 0.5

(b) 3 + \(\frac{7}{10} \) = 3+ 0.7 = 3.7

(c) 200 + 60 + 5 + \(\frac{1}{10} \) = 265+ 0.5 = 265.5

(d) 70 +\(\frac{8}{10} \) = 70+ 0.8 = 70.8

(e) \(\frac{88}{10} \) = 8.8

(f) \(4\frac{2}{10} \) = \(\frac{42}{10} \) = 4.2

(g) \(\frac{3}{2} \) = \(\frac{3×5}{2×5} \) = \(\frac{15}{10} \) = 1.5

(h) \(\frac{2}{5} \) = \(\frac{2×2}{5×2} \) = \(\frac{4}{10} \) = 0.4

(i) \(\frac{12}{5} \) = \(\frac{12×2}{5×2} \) = \(\frac{24}{10} \) = 2.4

(j) \(3\frac{3}{5} \) = \(\frac{18}{5} \) = \(\frac{18×2}{5×2} \)= \(\frac{36}{10} \) = 3.6

(k) \(4\frac{1}{2} \) = \(\frac{9}{2} \) = \(\frac{9×5}{2×5} \)
= \(\frac{45}{10} \) = 4.5

Q.5 Write the following decimals as fractions. Reduce the fractions to lowest form.

(a) 0.6

(b) 2.5

(c) 1.0

(d) 3.8

(e) 13.7

(f) 21.2

(g) 6.4

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Answer :

(a) 0.6 = 6 / 10 = 3 / 5

(b) 2.5 = 25 / 10 = 5 / 2

(c) 1.0 = 1 = 1

(d) 3.8 = 38 / 10 = 19 / 5

(e) 13. 7 = 137 / 10

(f) 21.2 = 212 / 10 = 106 / 5

(g) 6.4 = 64 / 10 = 32 / 5

Q.6 Express the following as cm using decimals.

(a) 2 mm

(b) 30 mm

(c) 116 mm

(d) 4 cm 2 mm

(e) 162 mm

(f) 83 mm

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Answer :

We know that 10 mm = 1 cm.

\(\therefore \) 1mm = \(\frac{1}{10} \) cm

(a) 2 mm = 2 × \(\frac{1}{10} \) cm = \(\frac{2}{10} \) cm = 0.2 cm

(b) 30 mm = 30 × \(\frac{1}{10} \) cm = 3cm

(c) 116 mm =116 × \(\frac{1}{10} \) cm = \(\frac{116}{10} \) cm = 11.6 cm

(d) 4 cm 2 mm = 4 cm+ 2× \(\frac{1}{10} \) cm = 4 + 0.2 = 4.2 cm

(e) 162 mm = 162 × \(\frac{1}{10} \) cm = \(\frac{162}{10} \) cm = 16.2

(f) 83 mm = 83 × \(\frac{1}{10} \) cm = \(\frac{83}{10} \) cm = 8.3 cm

Q.7 Between which two whole numbers on the number line are the given numbers lie?

Which of these whole numbers is nearer the number?
(a) 0.8
(b) 5.1
(c) 2.6
(d) 6.4
(e) 9.1
(f) 4.9

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Answer :

(a) 0.8 lies between the whole numbers 0 and 1.

(a) 5.1 lies between the whole numbers 5 and 6.

(b) 2.6 lies between the whole numbers 2 and 3.

(c) 6.4 lies between the whole numbers 6 and 7.

(d) 9.1 lies between the whole numbers 9 and 10.

(e) 4.9 lies between the whole numbers 4 and 5.

Q.10 (a) The length of Ramesh’s notebook is 9 cm 5 mm. What will be its length in cm?

(b) The length of a young gram plant is 65 mm. Express its length in cm.

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Answer :

(a) The length of Ramesh notebook is 9 cm 5 mm

The length in cm is 9 + \(\frac{5}{10} \) cm = 9.5 cm

(b) The length of a gram plant is 65 mm

Hence, the length in cm is \(\frac{65}{10} \) = 6.5 cm

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Answer :

(a) 3 + \(\frac{2}{10} \) + \(\frac{5}{100} \)

= 3 + 0.2 + 0.05

= 3.25

(b) 100 + 2 + \(\frac{6}{10} \) + \(\frac{3}{100} \)

= 102 + 0.6 + 0.03

= 102.63

(c) 30 + \(\frac{2}{100} \) + \(\frac{5}{1000} \)

= 30 + 0.02 + 0.005

= 30.025

(d) 200 + 10 + 1 + \(\frac{9}{10} \) + \(\frac{2}{1000} \)

= 211 + 0.9 + 0.002

= 211.902

(e) 10 + 2 + \(\frac{2}{10} \) + \(\frac{4}{100} \) + \(\frac{1}{1000} \)

= 12 + 0.2 + 0.04 + 0.001

= 12.241

Q.4 Write each of the following as decimals.

(a) 20 + 9 + \(\frac{4}{10} \) + \(\frac{1}{100} \)

(b) 137 + \(\frac{5}{100} \)

(c) \(\frac{7}{10} \) + \(\frac{6}{100} \) + \(\frac{4}{1000} \)

(d) 23 + \(\frac{2}{10} \) + \(\frac{6}{1000} \)

(e) 700 + 20 + 5 + \(\frac{9}{100} \)

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Answer :

(a) 20 + 9 + \(\frac{4}{10} \) + \(\frac{1}{100} \)

= 29 + 0.4 + 0.01

= 29.41

(b) 137 + \(\frac{5}{100} \)

= 137 + 0.05

= 137.05
(c) \(\frac{7}{10} \) + \(\frac{6}{100} \) + \(\frac{4}{1000} \)

= 0.7 + 0.06 + 0.004

=0.764

(d) 23 + \(\frac{2}{10} \) + \(\frac{6}{1000} \)

= 23 + 0.2 + 0.006

= 23.206

(e) 700 + 20 + 5 + \(\frac{9}{100} \)

= 725 + 0.09

= 725.09

Q.5 Write each of the following decimals in words.

(a) 0.03

(b) 1.20

(c) 108.56

(d) 10. 07

(e) 0.032

(f) 5.008

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Answer :

(a) 0.03 = zero point zero three

(b) 1.20 = one point two zero

(c) 108.56 = one hundred eight point five six

(d) 10.07 = ten point zero seven

(e) 0.032 = zero point zero three two

(f) 5.008 = five point zero zero eight

Q.6 Between which two numbers in tenths place on the number line does each of the given number lie?

(a) 0.06
(b) 0.45
(c) 0.19
(d) 0.66
(e) 0.92
(f) 0.57

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Answer :

(a) 0.06 lies between 0 and 0.1 in tenths place

(b) 0.45 lies between 0.4 and 0.5 in tenths place

(c) 0.19 lies between 0.1 and 0.2 in tenths place

(d) 0.66 lies between 0.6 and 0.7 in tenths place

(e) 0.92 lies between 0.9 and 1.0 in tenths place

(f) 0.57 lies between 0.5 and 0.6 in tenths place

Q.7 Write as fractions in lowest terms.

(a) 0.60
(b) 0.05
(c) 0.75
(d) 0.18
(e) 0.25
(f) 0.125
(g) 0.066

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Answer :

(a) 0.60 = \(\frac{60}{100} \) = \(\frac{60÷20}{100÷20} \) =\(\frac{3}{5} \)

(b) 0.05 = \(\frac{5}{100} \) = \(\frac{5÷5}{100÷5} \) =\(\frac{1}{20} \)

(c) 0.75 = \(\frac{75}{100} \) = \(\frac{75÷25}{100÷25} \) =\(\frac{3}{4} \)

(d) 0.18 = \(\frac{18}{100} \) = \(\frac{18÷2}{100÷2} \) =\(\frac{9}{50} \)

(e) 0.25 = \(\frac{25}{100} \) = \(\frac{25÷25}{100÷25} \) =\(\frac{1}{4} \)

(f) 0.125 = \(\frac{125}{1000} \) = \(\frac{125÷125}{1000÷125} \) =\(\frac{1}{8} \)

(g) 0.066 = \(\frac{66}{1000} \) = \(\frac{66÷2}{1000÷2} \) =\(\frac{33}{500} \)

Q.1 Which is greater?

(a) 0.3 or 0.4
(b) 0.07 or 0.02
(c) 3 or 0.8
(d) 0.5 or 0.05
(e) 1.23 or 1.2
(f) 0.099 or 0.19
(g) 1.5 or 1.50
(h) 1.431 or 1.490
(i) 3.3 or 3.300
(j) 5.64 or 5.603

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Answer :

(a) 0.3 < 0.4

(b) 0.07 > 0.02

(c) 3 > 0.8

(d) 0.5 > 0.05

(e) 1.23 > 1.2

(f) 0.099 < 0.19

(g) 1.5 = 1.50

(h) 1.431 < 1.490

(i) 3.3 = 3.300

(j) 5.64 > 5.603

Q.1 Express as rupees using decimals.

(a) 5 paise
(b) 75 paise
(c) 20 paise
(d) 50 rupees 90 paise
(e) 725 paise

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Answer :

We know that 100 paise = 1 rupee

\(\therefore \) 1 paisa = \(\frac{1}{100} \)rupees

(a) 5 paise = 5 × \(\frac{1}{100} \) Rupees= \(\frac{5}{100} \) rupees = 0.05 rupees

(b) 75 paise = 75 × \(\frac{1}{100} \)rupees = \(\frac{75}{100} \)rupees = 0.75 rupees

(c) 20 paise = 20 × \(\frac{1}{100} \)rupees = \(\frac{20}{100} \)rupees = 0.2 rupees

(d) 50 rupees 90 paise = 50 + 90 × \(\frac{1}{100} \)rupees =50 + \(\frac{90}{100} \)rupees = 50.9 rupees

(e) 725 paise = 725 × \(\frac{1}{100} \)rupees = \(\frac{725}{100} \)rupees = 7.25 rupees

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Answer :

We know that there are 1000 m = 1 km

\(\therefore \) 1m = \(\frac{1}{1000} \)

(a) 8 m = 0.008 km

(b) 88 m = 0.088 km

(c) 8888 m = 8.888 km

(d) 70 km 5 m = 70.005 km

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Answer :

We know that there are 1000 g = 1 kg

\(\therefore \) 1g = \(\frac{1}{1000} \) kg

(a) 2 g = 0.002 kg

(b) 100 g = 0.1 kg

(c) 3750 g = 3.750 kg

(d) 5 kg 8 g = 5.008 kg

(e) 26 kg 50 g = 26.05 kg

Q.1 Find the sum in each of the following:

(a) 0.007 + 8.5 + 30.08

(b) 15 + 0.632 + 13.8

(c) 27.076 + 0.55 + 0.004

(d) 25.65 + 9.005 + 3.7

(e) 0.75 + 10.425 + 2

(f) 280.69 + 25.2 + 38

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Answer :

(a) 0.007 + 8.5 + 30.08

= 00.007 + 08.500 + 30.080 = 38.587

(b) 15 + 0.632 + 13.8

= 15.000 + 0.632 + 13.800= 29.432

(c) 27.076 + 0.55 + 0.004

= 27.076 + 0.550+ 0.004 =27.630

(d) 25.65 + 9.005 + 3.7

= 25.650 + 9.005 + 3.700 = 38.355

(e) 0.75 + 10.425 + 2

= 0.750 + 10.425 + 2.000 = 13.175

(f) 280.69 + 25.2 + 38

= 280.69 + 25.20 + 38.00 = 343.89

Q.3 Radhika’s mother gave her Rs. 10.50 and her father gave her Rs. 15.80, find the total amount given to Radhika by the parents.

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Answer :

Amount given by Radhika’s mother = Rs. 10.50

Amount given by Radhika’s father = Rs. 15.80

Total amount given by her parents

= 10.50 + 15.80 = Rs. 26.30

Q.4 Nasreen bought 3 m 20 cm cloth for her shirt and 2 m 5 cm cloth for her trouser. Find the total length of cloth bought by her.

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Answer :

Cloth of shirt = 3 m 20 cm = 3.20 m

Cloth of trouser = 2 m 5 cm = 2.05 m

Total length of cloth is = 3.20 + 2.05 = 5.25 m

Q.5 Naresh walked 2 km 35 m in the morning and 1 km 7 m in the evening. How much distance did he walk in all?

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Answer :

Distance walked by Naresh in the morning

= 2 km 35 m = 2.035 km

Distance walked by him in the evening

= 1 km 7 m = 1.007 km

Total distance walked by Naresh is

= 2.035 + 1.007 = 3.042 km

Q.6 Sunita travelled 15 km 268 m by bus, 7 km 7 m by car and 500 m on foot in order to reach her school. How far is her school from her residence?

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Answer :

Distance travelled by bus

= 15 km 268 m = 15.268 km

Distance travelled by car = 7 km 7 m = 7.007 km

Distance walked by Sunita = 500 m = 0.500 km

Total distance of school from her residence is

15.268 + 7.007 + 0.500 = 22.775

Q.7 Ravi purchased 5 kg 400 g rice, 2 kg 20 g sugar and 10 kg 850 g flour. Find the total weight of his purchases.

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Answer :

Weight of rice = 5 kg 400 g = 5.400 kg

Weight of sugar = 2 kg 20 g = 2.020 kg

Weight of flour = 10 kg 850 g = 10.850 kg

Total weight of his purchases is

5.400 + 2.020 + 10.850 = 18.270

Q.1 Subtract:

(a) Rs. 18.25 from Rs. 20.75

(b) 202.54 m from 250 m

(c) Rs. 5.36 from Rs. 8.40

(d) 2.051 km from 5.206 km

(e) 0.314 kg from 2.107 kg

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Answer :

(a) Rs.18.25 from Rs. 20.75

= 20.75 – 18.25

= Rs. 2.50

(b) 202.54 m from 250 m

= 250 m – 202.54 m

= 250.00 m – 202.54 m

= 47.46 m

(c) Rs. 5.36 from Rs. 8.40

= Rs 8.40 – Rs 5.36

= Rs 3.04

(d) 2.051 km from 5.206 km

= 5.206 km – 2.051 km

= 3.155 km

(e) 0.314 kg from 2.107 kg

= 2.107 kg – 0.314 kg

= 1.793 kg

Q.3 Raju bought a book for Rs 35.65. He gave Rs 50 to the shopkeeper. How much money did he get back from the shopkeeper?

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Answer :

Cost of book = Rs 35.65

Money paid by him to the shopkeeper = Rs 50

\(\therefore \) Money got back by him

= Rs 50 – Rs 35.65 = Rs 50.00 – Rs 35.65

= Rs 14.35

Q.5 Tina had 20 m 5 cm long cloth. She cuts 4 m 50 cm length of cloth from this for making a curtain. How much cloth is left with her?

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Answer :

Length of cloth had by Tina

= 20 m 5 cm = 20.05 m

Length of cloth cut by her

= 4 m 50 cm = 4.50 m

\(\therefore \) Length of cloth left with her = 20.05 m -4.50 m

= 15.55 m

Q.6 Namita travels 20 km 50 m every day. Out of this she travels 10 km 200 m by bus and the rest by auto. How much distance does she travel by auto?

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Answer :

Distance travelled by Namita daily

= 20 km 50 m or 20.050 km

Distance travelled by her by bus

= 10 km 200 m or 10.200 km

Distance travelled by her by auto

= (20.050 – 10.200) km = 9.850 km

Q.7 Aakash bought vegetables weighing 10 kg. Out of this, 3 kg 500 g is onions, 2 kg 75 g is tomatoes and the rest is potatoes. What is the weight of the potatoes?

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Answer :

Weight of vegetables bought by Aakash = 10 kg

Weight of onions bought by him

= 3 kg 500 g = 3.500 kg

and weight of tomatoes bought by him

= 2 kg 75 g = 2.075 kg

Weight of potatoes = Weight of vegetable – (weight of onions + weight of tomatoes)

= 10.000 – (3.500 + 2.075)

= 10.000 – 5.575 = 4.425 kg

There are total 37 questions present in ncert solutions for class 6 maths chapter 8 decimals

There are total 0 long question/answers in ncert solutions for class 6 maths chapter 8 decimals

There are total 6 exercise present in ncert solutions for class 6 maths chapter 8 decimals