# NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Written by Team Trustudies
Updated at 2021-02-11

## NCERT solutions for class 6 Maths Chapter 8 Decimals Exercise 8.1

Q.1 Write the following numbers in the given table.

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Q.2 Write the following decimals in the place value table.
(a) 19.4
(b) 0.3
(c) 10.6
(d) 205.9

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Q.3 Write each of the following as decimals:
(a) Seven-tenths
(b) Two tens and nine-tenths
(c) Fourteen point six
(d) One hundred and two ones
(e) Six hundred point eight

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

(a) $\frac{7}{10}$ = 0.7
(b) 20 + $\frac{9}{10}$ = 20 . 9
(c) 14.6
(d) 100 + 2 = 102
(e) 600.8

Q.5 Write each of the following as decimals:
(a) $\frac{5}{10}$
(b) 3 + $\frac{7}{10}$
(c) 200 + 60 + 5 + $\frac{1}{10}$
(d) 70 +$\frac{8}{10}$
(e) $\frac{88}{10}$
(f) $4\frac{2}{10}$
(g) $\frac{3}{2}$
(h) $\frac{2}{5}$
(i) $\frac{12}{5}$
(j) $3\frac{3}{5}$
(k) $4\frac{1}{2}$

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

(a) $\frac{5}{10}$ = 0.5
(b) 3 + $\frac{7}{10}$ = 3+ 0.7 = 3.7
(c) 200 + 60 + 5 + $\frac{1}{10}$ = 265+ 0.5 = 265.5
(d) 70 +$\frac{8}{10}$ = 70+ 0.8 = 70.8
(e) $\frac{88}{10}$ = 8.8
(f) $4\frac{2}{10}$ = $\frac{42}{10}$ = 4.2
(g) $\frac{3}{2}$ = $\frac{3×5}{2×5}$ = $\frac{15}{10}$ = 1.5
(h) $\frac{2}{5}$ = $\frac{2×2}{5×2}$ = $\frac{4}{10}$ = 0.4
(i) $\frac{12}{5}$ = $\frac{12×2}{5×2}$ = $\frac{24}{10}$ = 2.4
(j) $3\frac{3}{5}$ = $\frac{18}{5}$ = $\frac{18×2}{5×2}$= $\frac{36}{10}$ = 3.6
(k) $4\frac{1}{2}$ = $\frac{9}{2}$ = $\frac{9×5}{2×5}$ = $\frac{45}{10}$ = 4.5

Q.5 Write the following decimals as fractions. Reduce the fractions to lowest form.
(a) 0.6
(b) 2.5
(c) 1.0
(d) 3.8
(e) 13.7
(f) 21.2
(g) 6.4

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

(a) 0.6 = 6 / 10 = 3 / 5
(b) 2.5 = 25 / 10 = 5 / 2
(c) 1.0 = 1 = 1
(d) 3.8 = 38 / 10 = 19 / 5
(e) 13. 7 = 137 / 10
(f) 21.2 = 212 / 10 = 106 / 5
(g) 6.4 = 64 / 10 = 32 / 5

Q.6 Express the following as cm using decimals.
(a) 2 mm
(b) 30 mm
(c) 116 mm
(d) 4 cm 2 mm
(e) 162 mm
(f) 83 mm

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

We know that 10 mm = 1 cm.
$?$ 1mm = $\frac{1}{10}$ cm
(a) 2 mm = 2 × $\frac{1}{10}$ cm = $\frac{2}{10}$ cm = 0.2 cm

(b) 30 mm = 30 × $\frac{1}{10}$ cm = 3cm

(c) 116 mm =116 × $\frac{1}{10}$ cm = $\frac{116}{10}$ cm = 11.6 cm

(d) 4 cm 2 mm = 4 cm+ 2× $\frac{1}{10}$ cm = 4 + 0.2 = 4.2 cm

(e) 162 mm = 162 × $\frac{1}{10}$ cm = $\frac{162}{10}$ cm = 16.2

(f) 83 mm = 83 × $\frac{1}{10}$ cm = $\frac{83}{10}$ cm = 8.3 cm

Q.7 Between which two whole numbers on the number line are the given numbers lie?
Which of these whole numbers is nearer the number? (a) 0.8 (b) 5.1 (c) 2.6 (d) 6.4 (e) 9.1 (f) 4.9

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

(a) 0.8 lies between the whole numbers 0 and 1.
(a) 5.1 lies between the whole numbers 5 and 6.
(b) 2.6 lies between the whole numbers 2 and 3.
(c) 6.4 lies between the whole numbers 6 and 7.
(d) 9.1 lies between the whole numbers 9 and 10.
(e) 4.9 lies between the whole numbers 4 and 5.

Q.8 Show the following numbers on the number line. (a) 0.2 (b) 1.9 (c) 1.1 (d) 2.5

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Q.9 Write the decimal number represented by the points.

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Point A represents 0.8
Point B represents 1.3
Point C represents 2.2
Point D represents 2.9

Q.10 (a) The length of Ramesh’s notebook is 9 cm 5 mm. What will be its length in cm?
(b) The length of a young gram plant is 65 mm. Express its length in cm.

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

(a) The length of Ramesh notebook is 9 cm 5 mm
The length in cm is 9 + $\frac{5}{10}$ cm = 9.5 cm
(b) The length of a gram plant is 65 mm
Hence, the length in cm is $\frac{65}{10}$ = 6.5 cm

## NCERT solutions for class 6 Maths Chapter 8 Decimals Exercise 8.2

Q.1 Complete the table with the help of these boxes and use decimals to write the number.

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Q.2 Write the numbers given in the following place value table in decimal form.

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

(a) 3 + $\frac{2}{10}$ + $\frac{5}{100}$
= 3 + 0.2 + 0.05
= 3.25
(b) 100 + 2 + $\frac{6}{10}$ + $\frac{3}{100}$
= 102 + 0.6 + 0.03
= 102.63
(c) 30 + $\frac{2}{100}$ + $\frac{5}{1000}$
= 30 + 0.02 + 0.005
= 30.025
(d) 200 + 10 + 1 + $\frac{9}{10}$ + $\frac{2}{1000}$
= 211 + 0.9 + 0.002
= 211.902
(e) 10 + 2 + $\frac{2}{10}$ + $\frac{4}{100}$ + $\frac{1}{1000}$
= 12 + 0.2 + 0.04 + 0.001
= 12.241

Q.3 Write the following decimals in the place value table.
(a) 0.29
(b) 2.08
(c) 19.60
(d) 148.32
(e) 200.812

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Q.4 Write each of the following as decimals.
(a) 20 + 9 + $\frac{4}{10}$ + $\frac{1}{100}$
(b) 137 + $\frac{5}{100}$
(c) $\frac{7}{10}$ + $\frac{6}{100}$ + $\frac{4}{1000}$
(d) 23 + $\frac{2}{10}$ + $\frac{6}{1000}$
(e) 700 + 20 + 5 + $\frac{9}{100}$

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

(a) 20 + 9 + $\frac{4}{10}$ + $\frac{1}{100}$
= 29 + 0.4 + 0.01
= 29.41
(b) 137 + $\frac{5}{100}$
= 137 + 0.05
= 137.05 (c) $\frac{7}{10}$ + $\frac{6}{100}$ + $\frac{4}{1000}$
= 0.7 + 0.06 + 0.004
=0.764
(d) 23 + $\frac{2}{10}$ + $\frac{6}{1000}$
= 23 + 0.2 + 0.006
= 23.206
(e) 700 + 20 + 5 + $\frac{9}{100}$
= 725 + 0.09
= 725.09

Q.5 Write each of the following decimals in words.
(a) 0.03
(b) 1.20
(c) 108.56
(d) 10. 07
(e) 0.032
(f) 5.008

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

(a) 0.03 = zero point zero three
(b) 1.20 = one point two zero
(c) 108.56 = one hundred eight point five six
(d) 10.07 = ten point zero seven
(e) 0.032 = zero point zero three two
(f) 5.008 = five point zero zero eight

Q.6 Between which two numbers in tenths place on the number line does each of the given number lie?
(a) 0.06 (b) 0.45 (c) 0.19 (d) 0.66 (e) 0.92 (f) 0.57

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

(a) 0.06 lies between 0 and 0.1 in tenths place
(b) 0.45 lies between 0.4 and 0.5 in tenths place
(c) 0.19 lies between 0.1 and 0.2 in tenths place
(d) 0.66 lies between 0.6 and 0.7 in tenths place
(e) 0.92 lies between 0.9 and 1.0 in tenths place
(f) 0.57 lies between 0.5 and 0.6 in tenths place

Q.7 Write as fractions in lowest terms.
(a) 0.60 (b) 0.05 (c) 0.75 (d) 0.18 (e) 0.25 (f) 0.125 (g) 0.066

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

(a) 0.60 = $\frac{60}{100}$ = $\frac{60÷20}{100÷20}$ =$\frac{3}{5}$
(b) 0.05 = $\frac{5}{100}$ = $\frac{5÷5}{100÷5}$ =$\frac{1}{20}$
(c) 0.75 = $\frac{75}{100}$ = $\frac{75÷25}{100÷25}$ =$\frac{3}{4}$
(d) 0.18 = $\frac{18}{100}$ = $\frac{18÷2}{100÷2}$ =$\frac{9}{50}$
(e) 0.25 = $\frac{25}{100}$ = $\frac{25÷25}{100÷25}$ =$\frac{1}{4}$
(f) 0.125 = $\frac{125}{1000}$ = $\frac{125÷125}{1000÷125}$ =$\frac{1}{8}$
(g) 0.066 = $\frac{66}{1000}$ = $\frac{66÷2}{1000÷2}$ =$\frac{33}{500}$

## NCERT solutions for class 6 Maths Chapter 8 Decimals Exercise 8.3

Q.1 Which is greater?
(a) 0.3 or 0.4 (b) 0.07 or 0.02 (c) 3 or 0.8 (d) 0.5 or 0.05 (e) 1.23 or 1.2 (f) 0.099 or 0.19 (g) 1.5 or 1.50 (h) 1.431 or 1.490 (i) 3.3 or 3.300 (j) 5.64 or 5.603

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

(a) 0.3 < 0.4
(b) 0.07 > 0.02
(c) 3 > 0.8
(d) 0.5 > 0.05
(e) 1.23 > 1.2
(f) 0.099 < 0.19
(g) 1.5 = 1.50
(h) 1.431 < 1.490
(i) 3.3 = 3.300
(j) 5.64 > 5.603

## NCERT solutions for class 6 Maths Chapter 8 Decimals Exercise 8.4

Q.1 Express as rupees using decimals.
(a) 5 paise (b) 75 paise (c) 20 paise (d) 50 rupees 90 paise (e) 725 paise

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

We know that 100 paise = 1 rupee
$?$ 1 paisa = $\frac{1}{100}$rupees

(a) 5 paise = 5 × $\frac{1}{100}$ Rupees= $\frac{5}{100}$ rupees = 0.05 rupees
(b) 75 paise = 75 × $\frac{1}{100}$rupees = $\frac{75}{100}$rupees = 0.75 rupees
(c) 20 paise = 20 × $\frac{1}{100}$rupees = $\frac{20}{100}$rupees = 0.2 rupees
(d) 50 rupees 90 paise = 50 + 90 × $\frac{1}{100}$rupees =50 + $\frac{90}{100}$rupees = 50.9 rupees
(e) 725 paise = 725 × $\frac{1}{100}$rupees = $\frac{725}{100}$rupees = 7.25 rupees

Q.2 Express as metres using decimals.
(a) 15 cm (b) 6 cm (c) 2 m 45 cm (d) 9 m 7 cm (e) 419 cm

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

(a) 15 cm = 0.15 m
(b) 6 cm = 0.06 m
(c) 2 m 45 cm = 2.45 m
(d) 9 m 7 cm = 9.07 m
(e) 419 cm = 4.19 m

Q.3 Express as cm using decimals
(a) 5 mm (b) 60 mm (c) 164 mm (d) 9 cm 8 mm (e) 93 mm

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

We know that 1mm =$\frac{1}{10}$ = 0.1 cm
(a) 5 mm = 0.5 cm
(b) 60 mm = 6 cm
(c) 164 mm = 16.4 cm
(d) 9 cm 8 mm = 9.8 cm
(e) 93 mm = 9.3 cm

Q.4 Express as km using decimals.
(a) 8 m (b) 88 m (c) 8888 m (d) 70 km 5 m

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

We know that there are 1000 m = 1 km
$?$ 1m = $\frac{1}{1000}$
(a) 8 m = 0.008 km
(b) 88 m = 0.088 km
(c) 8888 m = 8.888 km
(d) 70 km 5 m = 70.005 km

Express as kg using decimals.
(a) 2 g (b) 100 g (c) 3750 g (d) 5 kg 8 g (e) 26 kg 50 g

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

We know that there are 1000 g = 1 kg
$?$ 1g = $\frac{1}{1000}$ kg
(a) 2 g = 0.002 kg
(b) 100 g = 0.1 kg
(c) 3750 g = 3.750 kg
(d) 5 kg 8 g = 5.008 kg
(e) 26 kg 50 g = 26.05 kg

## NCERT solutions for class 6 Maths Chapter 8 Decimals Exercise 8.5

Q.1 Find the sum in each of the following:
(a) 0.007 + 8.5 + 30.08
(b) 15 + 0.632 + 13.8
(c) 27.076 + 0.55 + 0.004
(d) 25.65 + 9.005 + 3.7
(e) 0.75 + 10.425 + 2
(f) 280.69 + 25.2 + 38

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

(a) 0.007 + 8.5 + 30.08
= 00.007 + 08.500 + 30.080 = 38.587
(b) 15 + 0.632 + 13.8
= 15.000 + 0.632 + 13.800= 29.432
(c) 27.076 + 0.55 + 0.004
= 27.076 + 0.550+ 0.004 =27.630
(d) 25.65 + 9.005 + 3.7
= 25.650 + 9.005 + 3.700 = 38.355
(e) 0.75 + 10.425 + 2
= 0.750 + 10.425 + 2.000 = 13.175
(f) 280.69 + 25.2 + 38
= 280.69 + 25.20 + 38.00 = 343.89

Q.2 Rashid spent Rs. 35.75 for Maths book and Rs. 32.60 for Science book. Find the total amount spent by Rashid.

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Cost of Maths book = Rs. 35.75
Cost of Science book = Rs. 32.60
Total amount spent by Rashid is
= 35.75 + 32.60 =Rs. 68.35

Q.3 Radhika’s mother gave her Rs. 10.50 and her father gave her Rs. 15.80, find the total amount given to Radhika by the parents.

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Amount given by Radhika’s mother = Rs. 10.50
Amount given by Radhika’s father = Rs. 15.80
Total amount given by her parents
= 10.50 + 15.80 = Rs. 26.30

Q.4 Nasreen bought 3 m 20 cm cloth for her shirt and 2 m 5 cm cloth for her trouser. Find the total length of cloth bought by her.

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Cloth of shirt = 3 m 20 cm = 3.20 m
Cloth of trouser = 2 m 5 cm = 2.05 m
Total length of cloth is = 3.20 + 2.05 = 5.25 m

Q.5 Naresh walked 2 km 35 m in the morning and 1 km 7 m in the evening. How much distance did he walk in all?

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Distance walked by Naresh in the morning
= 2 km 35 m = 2.035 km
Distance walked by him in the evening
= 1 km 7 m = 1.007 km
Total distance walked by Naresh is
= 2.035 + 1.007 = 3.042 km

Q.6 Sunita travelled 15 km 268 m by bus, 7 km 7 m by car and 500 m on foot in order to reach her school. How far is her school from her residence?

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Distance travelled by bus
= 15 km 268 m = 15.268 km
Distance travelled by car = 7 km 7 m = 7.007 km
Distance walked by Sunita = 500 m = 0.500 km
Total distance of school from her residence is
15.268 + 7.007 + 0.500 = 22.775

Q.7 Ravi purchased 5 kg 400 g rice, 2 kg 20 g sugar and 10 kg 850 g flour. Find the total weight of his purchases.

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Weight of rice = 5 kg 400 g = 5.400 kg
Weight of sugar = 2 kg 20 g = 2.020 kg
Weight of flour = 10 kg 850 g = 10.850 kg
Total weight of his purchases is
5.400 + 2.020 + 10.850 = 18.270

## NCERT solutions for class 6 Maths Chapter 8 Decimals Exercise 8.6

Q.1 Subtract:
(a) Rs. 18.25 from Rs. 20.75
(b) 202.54 m from 250 m
(c) Rs. 5.36 from Rs. 8.40
(d) 2.051 km from 5.206 km
(e) 0.314 kg from 2.107 kg

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

(a) Rs.18.25 from Rs. 20.75
= 20.75 – 18.25
= Rs. 2.50
(b) 202.54 m from 250 m
= 250 m – 202.54 m
= 250.00 m – 202.54 m
= 47.46 m
(c) Rs. 5.36 from Rs. 8.40
= Rs 8.40 – Rs 5.36
= Rs 3.04
(d) 2.051 km from 5.206 km
= 5.206 km – 2.051 km
= 3.155 km
(e) 0.314 kg from 2.107 kg
= 2.107 kg – 0.314 kg
= 1.793 kg

Q2 Find the value of:
(a) 9.756 – 6.28
(b) 21.05 – 15.27
(c) 18.5 – 6.79
(d) 11.6 – 9.847

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

(a) 9.756 – 6.25 = 9.756 – 6.250 = 3.506
(b) 21.05 – 15.27 = 5.78
(c) 18.5 – 6.79 = 18.50 – 6.79 = 11.71
(d) 11.6 – 9.847 = 11.600 – 9.847 = 1.753

Q.3 Raju bought a book for Rs 35.65. He gave Rs 50 to the shopkeeper. How much money did he get back from the shopkeeper?

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Cost of book = Rs 35.65
Money paid by him to the shopkeeper = Rs 50
$?$ Money got back by him
= Rs 50 – Rs 35.65 = Rs 50.00 – Rs 35.65
= Rs 14.35

Q.4 Rani had Rs18.50. She bought one ice-cream for Rs 11.75. How much money does she have now?

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

She bought ice-cream for Rs11.75
$?$Money left with Rani = Rs 18.50 – Rs11.75 = Rs 6.75

Q.5 Tina had 20 m 5 cm long cloth. She cuts 4 m 50 cm length of cloth from this for making a curtain. How much cloth is left with her?

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Length of cloth had by Tina
= 20 m 5 cm = 20.05 m
Length of cloth cut by her
= 4 m 50 cm = 4.50 m
$?$ Length of cloth left with her = 20.05 m -4.50 m
= 15.55 m

Q.6 Namita travels 20 km 50 m every day. Out of this she travels 10 km 200 m by bus and the rest by auto. How much distance does she travel by auto?

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Distance travelled by Namita daily
= 20 km 50 m or 20.050 km
Distance travelled by her by bus
= 10 km 200 m or 10.200 km
Distance travelled by her by auto
= (20.050 – 10.200) km = 9.850 km

Q.7 Aakash bought vegetables weighing 10 kg. Out of this, 3 kg 500 g is onions, 2 kg 75 g is tomatoes and the rest is potatoes. What is the weight of the potatoes?

NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Weight of vegetables bought by Aakash = 10 kg
Weight of onions bought by him
= 3 kg 500 g = 3.500 kg
and weight of tomatoes bought by him
= 2 kg 75 g = 2.075 kg
Weight of potatoes = Weight of vegetable – (weight of onions + weight of tomatoes)
= 10.000 – (3.500 + 2.075)
= 10.000 – 5.575 = 4.425 kg

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