Q.1 Solve

(a)

(b)

(c)

(d)

(e)

(f)

(g)

(h)

(i)

(j)

(k)

(l)

(m)

(n)

NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Answer :

(a)

LCM of 7 and 3 = 21

=

=

(b)

LCM of 10 and 15 = 30

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=

(c)

LCM of 9 and 7 = 63

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=

(d)

LCM of 7 and 3 = 21

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=

(e)

LCM of 5 and 6 = 30

=

=

(f)

LCM of 5 and 3 = 15

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=

(g)

LCM of 4 and 3 = 12

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=

(h)

LCM of 6 and 3 = 6

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=

(i)

LCM of 3, 4 and 2 = 12

(j)

LCM of 2, 3 and 6 = 6

(k)

=

=

(l)

=

LCM of 3 and 4 = 12

=

=

(m)

(n)

LCM of 3 and 2 = 6

=

=

Q.2 Sarita bought

NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Answer :

Length of ribbon bought by Sarita =

Length of ribbon bought by Lalita =

LCM of 5 and 4 = 20

=

=

Q.3 Naina was given

NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Answer :

Fraction of cake Naina got =

Fraction of cake Najma got =

Total amount of cake given to both of them =

LCM of 2 and 3 = 6

=

=

Q. 4. Fill in the boxes:

(a)

(b)

(c)

NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Answer :

(a)

Or,

=

=

Or,

=

=

(C)

Or,

Or,

Or,

Or,

Q6 A piece of wire

NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Answer :

Total length of wire =

Length of one piece of wire =

Length of other piece of wire = Length of the original wire and this one piece of wire

=

=

=

=

Q.7 Nandini’s house is

NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Answer :

Distance of the school from house =

Distance she travelled by bus =

Distance walked by Nandini = Total distance of the school – Distance she travelled by bus

=

=

=

=

Q.8 Asha and Samuel have bookshelves of the same size partly filled with books. Asha’s shelf is

NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Answer :

Fraction of Asha’s bookshelf =

Fraction of Samuel’s bookshelf =

By cross multiplication

5×5 and 6×2

25 > 12

Difference =

=

=

=

Q.9 Jaidev takes

NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Answer :

Time taken by Jaidev to walk across the school ground =

Time taken by Rahul to walk across the school ground =

By cross multiplication

11×4 and 5×7

44 > 35

Difference =

=

=

=

NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Answer :

(i) Number of parts = 4

Shaded portion = 2

(ii) Number of parts = 9

Shaded portion = 8

(iii) Number of parts = 8

Shaded portion = 4

(iv) Number of parts = 4

Shaded portion = 1

(v) Number of parts = 7

Shaded portion = 3

(vi) Number of parts = 12

Shaded portion = 3

(vii) Number of parts = 10

Shaded portion = 10

(viii) Number of parts = 9

Shaded portion = 4

(ix) Number of parts = 8

Shaded portion = 4

(x) Number of parts = 2

Shaded portion = 1

NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Answer :

(i) The parts are not equal

Hence, this is not

(ii) the parts are not equal

Hence, Shaded portion is not

(iii) the parts are not equal

Hence, Shaded portion is not

Q.6 Arya, Abhimanyu, and Vivek shared lunch. Arya has brought two sandwiches, one made of vegetable and one of jam. The other two boys forgot to bring their lunch. Arya agreed to share his sandwiches so that each person will have an equal share of each sandwich.

(a) How can Arya divide his sandwiches so that each person has an equal share?

(b) What part of a sandwich will each boy receive?

NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Answer :

(a) Arya has divided the sandwich into 3 equal parts. So each person will get one part.

(b) Each boy receive

Q.7 Kanchan dyes dresses. She had to dye 30 dresses. She has so far finished 20 dresses. What fraction of dresses has she finished?

NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Answer :

Total number of dresses to be dyed = 30

Number of dresses finished = 20

NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Answer :

Natural numbers between 2 and 12 are;

2,3,4, 5, 6, 7, 8, 9, 10,11, 12

No. of given natural numbers = 11

No. of prime numbers = 5

Hence, fraction =

NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Answer :

Natural numbers from 102 to 113 are;

102,103,104,105,106, 107,108, 109,110, 111, 112,113

Total number of given natural numbers = 12

Prime numbers are 103, 107, 109, 113

Hence, fraction =

Q.11 Kristin received a CD player for her birthday. She bought 3 CDs and received 5 others as gifts. What fraction of her total CDs did she buy and what fraction did she receive as gifts?

NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Answer :

Number of CDs bought by her from the market = 3

Number of CDs received as gifts = 5

Therefore Total number of CDs = 3 + 5 = 8

Therefore Fraction of CDs (bought) =

and the fraction of CDs (gifted) =

Q.2 Express the following as mixed fractions:

(a)

(b)

(c)

(d)

(e)

(f)

NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Answer :

(a)

(b)

(c)

(d)

(e)

(f)

Q.3 Express the following as improper fractions:

(a)

(b)

(c)

(d)

(e)

(f)

NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Answer :

(a)

(b)

(c)

(d)

(e)

(f)

NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Answer :

(a)

(i) The shaded portion is

(ii) The shaded portion is

(iii) The shaded portion is

(iv) The shaded portion is

Hence, all fractions are equivalent.

(b)

(i) The shaded portion is

(ii) The shaded portion is

(iii) The shaded portion is

(iv) The shaded portion is

Hence, all fractions are not equivalent.

NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Answer :

(a)

(b)

(c)

(d)

(e)

(i)

(ii)

(iii)

(iv)

(v)

The following are the equivalent fractions

(a) and (ii)

(b) and (iv)

(c) and (i)

(d) and (v)

(e) and (iii)

Q.3 Replace

(a)

(b)

(c)

(d)

(e)

NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Answer :

(a)

(b)

(c)

(d)

(e)

Q.4 Find the equivalent fraction of

(a) denominator 20

(b) numerator 9

(c) denominator 30

(d) numerator 27

NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Answer :

(a) We require denominator 20

Let M be the numerator of the fractions

5 × M = 20 × 3

M = (20 × 3) ÷ 5 = 12

Therefore the required fraction is

(b) We require numerator 9

Let N be the denominator of the fractions

3 × N = 9 × 5

N = (9 × 5) ÷ 3 = 15

Therefore the required fraction is

(c) We require denominator 30

Let D be the numerator of the fraction

5 × D = 3 × 30

D = (3 × 30) ÷ 5

= 18

Therefore the required fraction is

(d) We require numerator 27

Let X be the denominator of the fraction

3 × X = 5 × 27

X = (5 × 27) ÷ 3 = 45

Therefore the required fraction is

NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Answer :

(a) Given numerator = 9

X × 36 = 9 × 48

X = (9 × 48) / 36

X = 12

Hence, the equivalent fraction is

(b) Given, denominator = 4

X × 48 = 4 × 36

X = (4 × 36) / 48 = 3

Hence, the equivalent fraction is

Q.6 Check whether the given fractions are equivalent:

(a)

(b)

(c)

NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Answer :

(a) Given

We have 5× 54 = 270

9 × 30 = 270

5 × 54 = 9 × 30

Hence,

(b) Given

We have 3 × 50 = 150

10 × 12 = 120

3 × 50

Hence,

(c) Given

We have 7 × 11 = 77

5 × 13 = 65

7 × 11

Hence,

Q.7 Reduce the following fractions to simplest form:

(a)

(b)

(c)

(d)

(e)

NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Answer :

(a)

=

(b)

=

(c)

=

(d)

=

(e)

=

Q.8 Ramesh had 20 pencils, Sheelu had 50 pencils and Jamaal had 80 pencils. After 4 months, Ramesh used up 10 pencils, Sheelu used up 25 pencils and Jamaal used up 40 pencils. What fraction did each use up? Check if each has used up an equal fraction of her/his pencils?

NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Answer :

Total number of pencils Ramesh had = 20

Number of pencils used by Ramesh = 10