NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Answer :
(a)
LCM of 7 and 3 = 21
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(b)
LCM of 10 and 15 = 30
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(c)
LCM of 9 and 7 = 63
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(d)
LCM of 7 and 3 = 21
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(e)
LCM of 5 and 6 = 30
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(f)
LCM of 5 and 3 = 15
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(g)
LCM of 4 and 3 = 12
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(h)
LCM of 6 and 3 = 6
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(i)
LCM of 3, 4 and 2 = 12
(j)
LCM of 2, 3 and 6 = 6
(k)
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(l)
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LCM of 3 and 4 = 12
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(m)
(n)
LCM of 3 and 2 = 6
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Q.2 Sarita bought
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Answer :
Length of ribbon bought by Sarita =
Length of ribbon bought by Lalita =
LCM of 5 and 4 = 20
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Q.3 Naina was given
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Answer :
Fraction of cake Naina got =
Fraction of cake Najma got =
Total amount of cake given to both of them =
LCM of 2 and 3 = 6
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Q6 A piece of wire
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Answer :
Total length of wire =
Length of one piece of wire =
Length of other piece of wire = Length of the original wire and this one piece of wire
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Q.7 Nandini’s house is
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Answer :
Distance of the school from house =
Distance she travelled by bus =
Distance walked by Nandini = Total distance of the school – Distance she travelled by bus
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Q.8 Asha and Samuel have bookshelves of the same size partly filled with books. Asha’s shelf is
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Answer :
Fraction of Asha’s bookshelf =
Fraction of Samuel’s bookshelf =
By cross multiplication
5×5 and 6×2
25 > 12
Difference =
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Q.9 Jaidev takes
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Answer :
Time taken by Jaidev to walk across the school ground =
Time taken by Rahul to walk across the school ground =
By cross multiplication
11×4 and 5×7
44 > 35
Difference =
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NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Answer :
(i) Number of parts = 4
Shaded portion = 2
(ii) Number of parts = 9
Shaded portion = 8
(iii) Number of parts = 8
Shaded portion = 4
(iv) Number of parts = 4
Shaded portion = 1
(v) Number of parts = 7
Shaded portion = 3
(vi) Number of parts = 12
Shaded portion = 3
(vii) Number of parts = 10
Shaded portion = 10
(viii) Number of parts = 9
Shaded portion = 4
(ix) Number of parts = 8
Shaded portion = 4
(x) Number of parts = 2
Shaded portion = 1
Q.6 Arya, Abhimanyu, and Vivek shared lunch. Arya has brought two sandwiches, one made of vegetable and one of jam. The other two boys forgot to bring their lunch. Arya agreed to share his sandwiches so that each person will have an equal share of each sandwich.
(a) How can Arya divide his sandwiches so that each person has an equal share?
(b) What part of a sandwich will each boy receive?
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Answer :
(a) Arya has divided the sandwich into 3 equal parts. So each person will get one part.
(b) Each boy receive
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Answer :
Natural numbers from 102 to 113 are;
102,103,104,105,106, 107,108, 109,110, 111, 112,113
Total number of given natural numbers = 12
Prime numbers are 103, 107, 109, 113
Hence, fraction =
Q.11 Kristin received a CD player for her birthday. She bought 3 CDs and received 5 others as gifts. What fraction of her total CDs did she buy and what fraction did she receive as gifts?
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Answer :
Number of CDs bought by her from the market = 3
Number of CDs received as gifts = 5
Therefore Total number of CDs = 3 + 5 = 8
Therefore Fraction of CDs (bought) =
and the fraction of CDs (gifted) =
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Answer :
(a)
(i) The shaded portion is
(ii) The shaded portion is
(iii) The shaded portion is
(iv) The shaded portion is
Hence, all fractions are equivalent.
(b)
(i) The shaded portion is
(ii) The shaded portion is
(iii) The shaded portion is
(iv) The shaded portion is
Hence, all fractions are not equivalent.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Answer :
(a)
(b)
(c)
(d)
(e)
(i)
(ii)
(iii)
(iv)
(v)
The following are the equivalent fractions
(a) and (ii)
(b) and (iv)
(c) and (i)
(d) and (v)
(e) and (iii)
Q.4 Find the equivalent fraction of
(a) denominator 20
(b) numerator 9
(c) denominator 30
(d) numerator 27
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Answer :
(a) We require denominator 20
Let M be the numerator of the fractions
5 × M = 20 × 3
M = (20 × 3) ÷ 5 = 12
Therefore the required fraction is
(b) We require numerator 9
Let N be the denominator of the fractions
3 × N = 9 × 5
N = (9 × 5) ÷ 3 = 15
Therefore the required fraction is
(c) We require denominator 30
Let D be the numerator of the fraction
5 × D = 3 × 30
D = (3 × 30) ÷ 5
= 18
Therefore the required fraction is
(d) We require numerator 27
Let X be the denominator of the fraction
3 × X = 5 × 27
X = (5 × 27) ÷ 3 = 45
Therefore the required fraction is
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Answer :
(a) Given numerator = 9
X × 36 = 9 × 48
X = (9 × 48) / 36
X = 12
Hence, the equivalent fraction is
(b) Given, denominator = 4
X × 48 = 4 × 36
X = (4 × 36) / 48 = 3
Hence, the equivalent fraction is
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Answer :
(a) Given
We have 5× 54 = 270
9 × 30 = 270
5 × 54 = 9 × 30
Hence,
(b) Given
We have 3 × 50 = 150
10 × 12 = 120
3 × 50
Hence,
(c) Given
We have 7 × 11 = 77
5 × 13 = 65
7 × 11
Hence,
Q.8 Ramesh had 20 pencils, Sheelu had 50 pencils and Jamaal had 80 pencils. After 4 months, Ramesh used up 10 pencils, Sheelu used up 25 pencils and Jamaal used up 40 pencils. What fraction did each use up? Check if each has used up an equal fraction of her/his pencils?
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Answer :
Total number of pencils Ramesh had = 20
Number of pencils used by Ramesh = 10