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Answer :
Given :
Radius (r) of capsule = \(\frac{3.5}{2} mm = 1.75 mm\)
We know that,
Volume of spherical capsule
= \(\frac{4}{3}{\pi}{r}^3\)
= \(\frac{4}{3} × \frac{22}{7} × {1.75}^3\) \({mm}^3\)
= \(22.458\) \({mm}^3\)
= \(22.46\) \({mm}^3\)(appro×.)
Therefore ,the volume of the spherical capsule is \(22.46\) \({mm}^3\).