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Answer :
i) A grouped frequency distribution table of class size 2 has to be constructed.
The
class intervals will be -84 - 86, 86 - 88, and -99 - 90...
By observing the data given above, the required table can be constructed as follows.
Relative Humidity (in %) | Number of days (frequency) |
84 - 86 | 1 |
86 - 88 | 1 |
88 - 90 | 2 |
90 - 92 | 2 |
92 - 94 | 7 |
94 - 96 | 6 |
96 - 98 | 7 |
98 - 100 | 4 |
Total | 30 |