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The following table gives the distribution of students of two sections according to the marks obtained by them:
| Section A | Section B | ||
| Marks | Frequency | Marks | Frequency |
| 0 - 10 | 3 | 0 - 10 | 5 |
| 10 - 20 | 9 | 10 - 20 | 19 |
| 20 - 30 | 17 | 20 - 30 | 15 |
| 30 - 40 | 12 | 30 - 40 | 10 |
| 40 - 50 | 9 | 40 - 50 | 1 |
From the two polygons compare the performance of the two sections.
Answer :
We can find the class marks Of the given class intervals by using the following formula.
\(Class mark = \frac{Upper Class Limit + Lower Class Limit}{2}\)
| Section A | Section B | ||||
| Marks | Class Marks | Frequency | Marks | Class Marks | Frequency |
| 0 - 10 | 5 | 3 | 0 - 10 | 5 | 5 |
| 10 - 20 | 15 | 9 | 10 - 20 | 15 | 19 |
| 20 - 30 | 25 | 17 | 20 - 30 | 25 | 15 |
| 30 - 40 | 35 | 12 | 30 - 40 | 35 | 10 |
| 40 - 50 | 45 | 9 | 40 - 50 | 45 | 1 |
Taking class marks on x-axis and frequency on y-axis and choosing an appropriate scale (1 unit - 3 for y-axis), the frequency polygon can be drawn as follows.
It can be observed that the performance Of students Of section 'A' is better than the students of section 'B' in terms of good marks.