Premium Online Home Tutors
3 Tutor System
Starting just at 265/hour

The following table gives the distribution of students of two sections according to the marks obtained by them:
Section A Section B
MarksFrequencyMarksFrequency
0 - 1030 - 105
10 - 20910 - 2019
20 - 301720 - 3015
30 - 401230 - 4010
40 - 50940 - 501
Represent the marks of the students of both the sections on the same graph by two frequency polygons.
From the two polygons compare the performance of the two sections.


Answer :

We can find the class marks Of the given class intervals by using the following formula.

\(Class mark = \frac{Upper Class Limit + Lower Class Limit}{2}\)

Section A Section B
MarksClass MarksFrequencyMarksClass MarksFrequency
0 - 10530 - 1055
10 - 2015910 - 201519
20 - 30251720 - 302515
30 - 40351230 - 403510
40 - 5045940 - 50451


Taking class marks on x-axis and frequency on y-axis and choosing an appropriate scale (1 unit - 3 for y-axis), the frequency polygon can be drawn as follows.
image

It can be observed that the performance Of students Of section 'A' is better than the students of section 'B' in terms of good marks.

NCERT solutions of related questions for Statistics

NCERT solutions of related chapters class 9 maths

NCERT solutions of related chapters class 9 science