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The runs scored by two teams A and B on the first 60 balls in a cricket match are given below : No. of ballsTeam ATeam B 1 - 625 7 - 1216 13 - 1882 19 - 24910 25 - 3045 31 - 3656 37 - 4263 43 - 48104 49 - 5468 55 - 60210 Represent the data of both the teams on the same graph by frequency polygons.

It can be observed that the class inter,zals of the given data are not continuous. There is a gap of I in between them.

Therefore, has to be added to the upper class limits and 0.5 has to be subtracted from the lower class limits.Also, class mark of each interval can be found by using the following formula.

$$Class mark = \frac{Upper Class Limit + Lower Class Limit}{2}$$
Continuous data with class mark of each class interval can Be represented as follows.

 No. of balls Class Mark Team A Team B 0.5 - 6.5 3.5 2 5 6.5 - 12.5 9.5 1 6 12.5 - 18.5 15.5 8 2 18.5 - 24.5 21.5 9 10 24.5 - 30.5 27.5 4 5 30.5 - 36.5 33.5 5 6 36.5 - 42.5 39.5 6 3 42.5 - 48.5 45.5 10 4 48.5 - 54.5 51.5 6 8 55.5 - 60.5 57.5 2 10

By taking class marks on X-axis and runs scored on y-axis, a frequency polygon can be constructed as follows.