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The runs scored by two teams A and B on the first 60 balls in a cricket match are given below :
No. of ballsTeam ATeam B
1 - 625
7 - 1216
13 - 1882
19 - 24910
25 - 3045
31 - 3656
37 - 4263
43 - 48104
49 - 5468
55 - 60210
Represent the data of both the teams on the same graph by frequency polygons.


Answer :

It can be observed that the class inter,zals of the given data are not continuous. There is a gap of I in between them.

Therefore, has to be added to the upper class limits and 0.5 has to be subtracted from the lower class limits.Also, class mark of each interval can be found by using the following formula.

\(Class mark = \frac{Upper Class Limit + Lower Class Limit}{2}\)
Continuous data with class mark of each class interval can Be represented as follows.

No. of ballsClass MarkTeam ATeam B
0.5 - 6.53.525
6.5 - 12.59.516
12.5 - 18.515.582
18.5 - 24.521.5910
24.5 - 30.527.545
30.5 - 36.533.556
36.5 - 42.539.563
42.5 - 48.545.5104
48.5 - 54.551.568
55.5 - 60.557.5210


By taking class marks on X-axis and runs scored on y-axis, a frequency polygon can be constructed as follows.

image

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