Eleven bags of wheat flour, each marked 5 kg, actually contained the following weights of flour (in kg):
4.97 5.05 5.08 5.03 5.00 5.06 5.08 4.98 5.04 5.07 5.00
Find the probability that any of these bags chosen at random contains more than 5 kg of flour.


Answer :

Number of total bags = 11
Number of bags containing more than 5 kg of flour = 7
Hence, required probability = \(P = \frac{7}{11}\)

Therefore, the probability that any of these bags chosen at random contains more than 5 kg of flour is \(\frac{7}{11}\).

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