# In Q.5, Exercise 14.2, you were asked to prepare a frequency distribution table, regarding the concentration of sulphur dioxide in the air in parts per million of a certain city for 30 days.Using this table, find the probability of the concentration of sulphur dioxide in the interval 0.12 - 0.16 on any of these days. Concentration of $$S\left(O_{2}\right)$$ (in ppm)Number of days (frequency) 0.00 - 0.044 0.04 - 0.089 0.08 - 0.129 0.12 - 0.162 0.16 - 0.204 0.20 - 0.242 Total30

Hence, required probability is $$P = \frac{2}{30} = \frac{1}{15}$$.
Therefore, the probability of the concentration of sulphur dioxide in the interval 0.12 - 0.16 on any of these days is $$\frac{1}{15}$$.