In Q.5, Exercise 14.2, you were asked to prepare a frequency distribution table, regarding the concentration of sulphur dioxide in the air in parts per million of a certain city for 30 days.
Using this table, find the probability of the concentration of sulphur dioxide in the interval 0.12 - 0.16 on any of these days.
Concentration of \(S\left(O_{2}\right) \) (in ppm)Number of days (frequency)
0.00 - 0.044
0.04 - 0.089
0.08 - 0.129
0.12 - 0.162
0.16 - 0.204
0.20 - 0.242
Total30


Answer :

Number days for which the concentration Of sulphur dioxide was in the interval of 0.12 - 0.16 = 2

Total number Of days = 30

Hence, required probability is \(P = \frac{2}{30} = \frac{1}{15}\).

Therefore, the probability of the concentration of sulphur dioxide in the interval 0.12 - 0.16 on any of these days is \(\frac{1}{15}\).

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