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| Concentration of \(S\left(O_{2}\right) \) (in ppm) | Number of days (frequency) |
| 0.00 - 0.04 | 4 |
| 0.04 - 0.08 | 9 |
| 0.08 - 0.12 | 9 |
| 0.12 - 0.16 | 2 |
| 0.16 - 0.20 | 4 |
| 0.20 - 0.24 | 2 |
| Total | 30 |
Answer :
Number days for which the concentration Of sulphur dioxide was in the interval of
0.12 - 0.16 = 2
Total number Of days = 30
Hence, required probability is \(P = \frac{2}{30} = \frac{1}{15}\).
Therefore, the probability of the concentration of sulphur dioxide in the interval 0.12 - 0.16 on any of these days is \(\frac{1}{15}\).