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Answer :

In \( ∆ \ BDE \)

\( \frac{DE}{BD} \ = \ cosec 30º \ => \ \frac{DE}{1.5} \ = \ 2 \)

=> \( DE \ = \ 2 × 1.5 \ = \ 3 \)

And in \( ∆ \ ABC \)

\( \frac{AC}{AB} \ = \ cosec 60º \ => \ \frac{AC}{3} \ = \ \frac{2}{ \sqrt{3}} \)

\( AC \ = \ \frac{2}{ \sqrt{3}} × 3 \ = \ 2\sqrt{3} \)

\(\therefore \) Length of slides are \( 3 \) m and \( 2\sqrt{3} \) m

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