Q4. The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower, is 30º. Find the height of the tower.
In $$∆ \ CAB$$, we have
$$\frac{AB}{CA} \ = \ tan30º$$
$$\frac{h}{30} \ = \ \frac{1}{ \sqrt{3}} \ => \ h \ = \ \frac{30}{ \sqrt{3}} \ = \ 10 \sqrt{3}$$
Hence, the height of the tower is $$10 \sqrt{3}$$ metres.