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Answer :

Let r be the radius of the circle whose circumference is equal to the sum of the circumference of two circles of radii 19 cm and 9 cm.

\(\therefore \) \( 2 \pi r \ = \ 2 \pi (19) \ + \ 2 \pi (9) \)

\( \Rightarrow \ r \ = \ 19 \ + \ 9 \ = \ 28 \)

Hence, the radius of the new circle is 28 cm.

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