Find the area of a sector of a circle with radius 6 cm if angle of the sector is 60°

We know that the area A of a sector of angle $$\theta$$ in a circle of radius r is given by $$A \ = \ \frac{ \theta}{360} \ × \ \pi r^2$$.
Here $$r \ = \ 6 \ cm$$, $$\theta \ = \ 60°$$
$$\therefore$$ $$A \ = \ \frac{60}{360} \ × \ \frac{22}{7} \ × \ 36 \$$
$$= \ ( \frac{132}{7} ) \ cm^2$$