Tick the correct answer in the following : Area of a sector of angle p (in degrees) of a circle with radius R is :
(a) \( \frac{p}{180} \ × \ 2\pi R \)
(b) \( \frac{p}{180} \ × \ \pi R^2 \)
(c) \( \frac{p}{360} \ × \ 2\pi R \)
(d) \( \frac{p}{720} \ × \ 2\pi R^2 \)

We know that area A of a sector of angle \(\theta\) in a circle of radius r is given by

\( A \ = \ \frac{ \theta }{360} \ × \ \pi r^2 \)

But here , \( r \ = \ R \) and \( \theta \ = \ p \)

\(\therefore \) \( A \ = \ \frac{p}{360} \ × \ \pi R^2 \ = \ \frac{p}{720} \ × \ 2\pi R^2 \)

\(\therefore \)(D) is the correct answer.