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Answer :

Area of the square ABCD \(= \ (14)^2 \ = \ 196 \) cm^{2}

Diameter of the semicircles = AD or BC = 14 cm

\(\therefore \) Radius of each semicircle \( = \ 7 \) cm

Area of the semicircular regions \( = \ 2 \ × \ \frac{1}{2} \pi \ r^2 \ = \ \pi r^2 \)

\( = \ \frac{22}{7} \ × \ 49 \ = \ 154 \)cm^{2}

\(\therefore \) Area of the shaded portion

= Area of the square ABCD - Area of the semicircular regions

\(= \ 196 \ - \ 154 \ = \ 42 \)cm^{2}

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