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Answer :
The area of the whole square ABCD \( = \ 4^2 \ = \ 16 \)cm2
The sum of the area of the four quadrants at the four corners of the square
= The area of a circle of radius 1 cm
\(= \ \frac{22}{7} \ × \ 1^2 \ = \ \frac{22}{7} \)cm2
The area of the circle of diameter 2 cm, i.e., radius 1cm
\( = \ \frac{22}{7} \ × \ 1^2 \ = \ \frac{22}{7} \) cm2
\(\therefore \).Area of the remaining portion = The Area of the square ABCD - sum of the areas of the 4 quadrants - Area of the circle
\(= \ 16 \ - \ \frac{22}{7} \ - \ \frac{22}{7} \ = \ \frac{112 \ - \ 22 \ - \ 22}{7} \)
\( = \ \frac{68}{7} \)cm2