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Answer :
Side of the square ABCD = AB
= 3 × diameter of circular design
\( = \ 3 \ × \ (2 \ × \ 7) \ = \ 42 \) cm
\(\therefore \) Area of the square ABCD \( = \ 42 \ × \ 42 \ = \ 1764 \) cm2
Area of one circular design \( = \ \pi r^2 \)
\( = \ \frac{22}{7} \ × \ 7 \ × \ 7 \ = \ 154 \) cm2
\(\therefore \) Area of 9 such designs \( = \ 9 \ × \ 154 \ = \ 1386 \) cm2
\(\therefore \) Area of the remaining portion of the handkerchief
= Area of the square ABCD - Area of 9 circular designs
\(= \ 1764 \ - \ 1386 \ = \ 378 \) cm2