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Answer :
(i) Area of quadrant \( = \ \frac{1}{4} \ \pi r^2 \)
\(= \ \frac{1}{4} \ × \ \frac{22}{7} \ × \ (3.5)^2 \)
\( = \ \frac{1}{4} \ × \ \frac{22}{7} \ × \ ( \frac{7}{2} )^2 \ = \ \frac{77}{8} \) cm2
(ii) Area of ∆ BOD = \( \frac{1}{2} \) Base × Height
\( = \ \frac{1}{2} \ (OB \ × \ OD) \)
\( = \ \frac{1}{2} (3.5 \ × \ 2) \ = \ \frac{7}{2} \) cm2
So, area of the shaded region
= Area of quadrant - Area of ∆ BOD
\(= \ \frac{77}{8} \ - \ \frac{7}{2} \ = \ \frac{49}{8} \) cm2