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# 2 cubes each of volume 64 cm3 are joined end to end. Find the surface area of the resulting cuboid.

Let the length of each edge of the cube be a cm.

Then, Volume $$= \ 64$$cm3

$$\Rightarrow \ a^3 \ = \ 64 \$$
$$\Rightarrow \ a \ = \ 4$$ cm

When two cubes of equal volumes (i.e., equal edges) are joined end to end, we get a cuboid such that its,

l = Length $$= \ 4 \ + \ 4 \ = \ 8$$ cm

b = Breadth = 4 cm

and h = Height = 4 cm

$$\therefore$$ Surface area of the cuboid = 2(lb + bh + hl)

$$= \ 2(8 \ × \ 4 \ + \ 4 \ × \ 4 \ + \ 4 \ × \ 8)$$

$$= 2(32 \ + \ 16 \ + \ 32)$$

$$= (2 \ × \ 80)$$

$$= \ 160$$ cm2