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Answer :
Let r cm be the radius and h cm be the height of the cylinder. Then.
\( r \ = \ \frac{5}{2} \ = \ 2.5 \)mm
\( h \ = \ (14 \ - \ 2 \ × \ \frac{5}{2}) \ = 14 \ - \ 5 \ = \ 9 \)mm
Also the radius of hemisphere \( = \ \frac{5}{2} \) cm
Now, surface area of the capsule = Curved surface of cylinder + Surface area of two hemispheres
\( = \ 2 \pi rh \ + \ 2 \ × \ 2\pi r^2 \ = \ 2\pi r(h \ + \ 2r) \)
\( = \ 2 \ × \ \frac{22}{7} \ × \ \frac{5}{2} \ × \ (9 \ + \ 2 \ × \ \frac{5}{2}) \ = \ 220 \) mm2