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Answer :
We have,
Height of the cylinderical part = 2.1 m
Diameter of the cylinderal part = 4 m
Radius of the cylinerical part = 2 m
Slant height of the conical part = 2.8 m
Thus, Total canvas used = Curved surface area of cylinder + Curved surface area of cone
\( = \ 2 \pi rh \ + \ \pi rl \ = \ \pi r(2h \ + \ l) \)
\(= \ \frac{22}{7} \ × \ 2 \ × \ (2 \ × \ 2.1 \ + \ 2.8) \ \)
\( = \ 44 \) m2
Now, cost of 1 m2 the canvas for the tent = Rs 500
So, cost of 44 m2 the canvas for the tent = Rs 44 × 500 = Rs 22000