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Answer :
Let h be the required height of the embankment.
The shape of the embankment will be like the shape of a cylinder of internal radius 1.5 m and external radius \(4 \ + \ 1.5 \ = \ 5.5 \) m
The volume of the embankment will be equal to the volume of earth dug out from the well.
Now, the volume of the earth = Volume of the cylindrical well
\( = \ \pi \ × \ (1.5)^2 \ × \ 14 \ = \ 31.5\pi \) m3
Also, the volume of the embankment
\(= \ \pi (5.52 \ - \ 1.52)h \ = \ \pi \ × \ 7 \ × \ 4h \)
\(= \ 28 \pi h \) m3
\(\therefore 28 \pi h \ = \ 31.5 \pi \)
\( \Rightarrow \ h \ = \ \frac{31.5}{28} \ = \ 1.125 \) m
Hence, the required height of the embankment = 1.125 m