A drinking glass is in the shape of a frustum of a cone of height 14 cm. The diameters of its two circular ends are 4 cm and 2 cm. Find the capacity of the glass.

Capacity of the glass, \(V \ = \ \frac{1}{3} \ × \pi \ × \ h \ (R^2 \ + \ r^2 \ + \ Rr) \)

Here, R = 2 cm , r = 1 cm , h = 14 cm

\( \therefore V \ = \ \frac{1}{3} \ × \frac{22}{7} \ × \ 14 \ (2^2 \ + \ 1^2 \ + \ 2 \ × \ 1) \ \)
\( = \ \frac{44}{3} \ × \ (4 \ + \ 1 \ + \ 2) \)

\(= \ \frac{44}{3} \ × \ 7 \ = \ \frac{308}{3} \) cm³