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Answer :
Here R = 10 cm, r = 4 cm and l = 15 cm
Area of the material used for making the fez = Surface area of frustum + The surface of top circular section
\( = \ \pi (R \ + \ r)l \ + \ \pi r^2 \)
\(= \ \frac{22}{7} (10 \ + \ 4) 15 \ + \ \frac{22}{7} \ × \ 4 \ × \ 4 \)
\(= \ \frac{22}{7} \ × \ 14 \ × \ 15 \ + \ \frac{352}{7} \)
\(= \ \frac{4620 \ + \ 352}{7} \ = \frac{4972}{7} \) cm2