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| Number of Plants | 0-2 | 2-4 | 4-6 | 6-8 | 8-10 | 10-12 | 12-14 |
| Number of Houses | 1 | 2 | 1 | 5 | 6 | 2 | 3 |
Answer :
In order to find the mean value, we will use direct method because the numerical value of \(f_i \) and \( x_i \) are small.
The midpoint of the given interval is found by formula:
\(Midpoint \ (x_i) \ = \ \frac{upper \ limit \ + \ lower \ limit}{2} \)
| No. of plants (Class interval) | No. of houses (Frequency \( (f_i) \) ) | Mid-point \((x_i)\) | \(f_i x_i \) |
| 0-2 | 1 | 1 | 1 |
| 2-4 | 2 | 3 | 6 |
| 4-6 | 1 | 5 | 5 |
| 6-8 | 5 | 7 | 35 |
| 8-10 | 6 | 9 | 54 |
| 10-12 | 2 | 11 | 22 |
| 12-14 | 3 | 13 | 39 |
| \( \sum \ f_i \ = \ 20 \) | \( \sum \ f_i x_i \ = \ 162 \) |