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# IF P(F) = 0.05, what is the probability of 'not E' ?

$$\because$$ $$P(E) \ + \ P (not \ E) \ = \ 1$$
$$\Rightarrow P (not \ E) \ = \ 1 \ - \ P(E) \$$
$$= \ 1 \ - \ 0.05 \ = \ 0.95$$