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# It is given that in a group of 3 students, the probability of 2 student not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday?

i.e, $$P(E) \ = \ 0.992$$
But $$P(E) \ + \ P( \overline{E} ) \ = \ 1$$
$$\Rightarrow P( \overline{E}) \ = \ 1 \ - \ P(E)$$
$$\Rightarrow 1 \ - \ 0.992 \ = \ 0.008$$
$$\therefore$$ The probability that the 2 students have the same birthday is 0.008.