Premium Online Home Tutors
3 Tutor System
Starting just at 265/hour
Answer :
There are \( 3 \ + \ 5 \ = \ 8 \) balls in a bag. Out of these 8 balls, one can be chosen in 8 ways.
\(\therefore \) Total number of elementary events = 8
(i) Since the bag contains 3 red balls, therefore, one red ball can be drawn in 3 ways.
\(\therefore \) Favourable number of elementary events = 3
Hence, P (getting a red ball ) \( = \ \frac{3}{8} \)
(ii) Since the bag contains 5 black balls along with 3 red ball, therefore, one black (not red) ball can be drawn in 5 ways.
\(\therefore \) , Favourable number of elementary events = 5
Hence, P(not getting a red ball) \( = \ \frac{5}{8} \)