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# A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is : (i) red? (ii) not red?

There are $$3 \ + \ 5 \ = \ 8$$ balls in a bag. Out of these 8 balls, one can be chosen in 8 ways.

$$\therefore$$ Total number of elementary events = 8

(i) Since the bag contains 3 red balls, therefore, one red ball can be drawn in 3 ways.

$$\therefore$$ Favourable number of elementary events = 3

Hence, P (getting a red ball ) $$= \ \frac{3}{8}$$

(ii) Since the bag contains 5 black balls along with 3 red ball, therefore, one black (not red) ball can be drawn in 5 ways.

$$\therefore$$ , Favourable number of elementary events = 5

Hence, P(not getting a red ball) $$= \ \frac{5}{8}$$