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A piggy bank contains hundred 50 p coins, fifty Re 1 coins, twenty Rs 2 coins and ten Rs 5 coins, If it is equally likely that one of the coins will fall out when the bank is turned upside down, what is the probability that the coin

(i) will be a 50 p coin?
(ii) will not be a Rs 5 coin?


Answer :


Total number of coins in the piggy bank = 100 + 50 + 20 + 10 = 180

\(\therefore \) Total number of elementary events = 180

(i) There are one hundred 50 paise coins in the piggy bank.

\(\therefore \) Favourable number of elementary events = 100

Hence, P(falling out of a 50p coin) \( = \ \frac{100}{180} \ = \ \frac{5}{9} \)

(ii) There are 100 + 50 + 20,i.e., 170 coins other than Rs 5 coin.

\(\therefore \) Favourable number of elementary events = 170

Hence, P(falling out of a coin other than Rs 5 coin)

\( \frac{170}{180} \ = \ \frac{17}{18} \)

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