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Answer :
Total number of possible outcomes = 8
\( P(E) \ = \ \frac{Number \ of \ favourable \ outcomes}{Total \ number \ of \ outcomes} \)
(i) Total number of favourable events (i.e. 8) = 1
P(pointing at 8) \( = \ \frac{1}{8} \ = \ 0.125 \)
(ii) Total number of odd numbers = 4 (1, 3, 5 and 7)
P(pointing at an odd number) \( = \ \frac{4}{8} \ = \ 0.5 \)
(iii) Total numbers greater than 2 = 6 (3, 4, 5, 6, 7 and 8)
P(pointing at a number greater than 4) \( = \ \frac{6}{8} \ = \ 0.75 \)
(iv) Total numbers less than 9 = 8 (1, 2, 3, 4, 5, 6, 7, and 8)
P(pointing at a number less than 9) \( = \ \frac{8}{8} \ = \ 1 \)