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Answer :
Total numbers of cards = 5
\( P(E) \ = \ \frac{Number \ of \ favourable \ outcomes}{Total \ number \ of \ outcomes} \)
(i) Numbers of queen = 1
P (picking a queen) \( = \ \frac{1}{5} \ = \ 0.2 \)
(ii) If the queen is drawn and put aside, the total numbers of cards left is (5-1) = 4
(a) Total numbers of ace = 1
P (picking an ace) \( = \ \frac{1}{4} \ = \ 0.25 \)
(b) Total numbers of queen = 0
P (picking a queen) \( = \ \frac{0}{4} \ = \ 0 \)