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Answer :
The total numbers of discs = 50
\( P(E) \ = \ \frac{Number \ of \ favourable \ outcomes}{Total \ number \ of \ outcomes} \)
(i) Total number of discs having two digit numbers = 81
(\(\because \) 1 to 9 are single digit numbers and so, total 2 digit numbers are 90 - 9 = 81)
P (bearing a two-digit number) \( = \ \frac{81}{90} \ = \ \frac{9}{10} \ = \ 0.9 \)
(ii) Total number of perfect square numbers = 9 (1, 4, 9, 16, 25, 36, 49, 64 and 81)
P (getting a perfect square number) \( =\ \frac{9}{90} \ = \ \frac{1}{10} \ = \ 0.1 \)
(iii) Total numbers which are divisible by 5 = 18 (5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85 and 90)
P (getting a number divisible by 5) \( = \ \frac{18}{90} \ = \ \frac{1}{5} \ = \ 0.2 \)