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# A child has a die whose six faces show the letters as given below: The die is thrown once. What is the probability of getting (i) A? (ii) D?

The total number of possible outcomes (or events) = 6

$$P(E) \ = \ \frac{Number \ of \ favourable \ outcomes}{Total \ number \ of \ outcomes}$$

(i) The total number of faces having A on it = 2

P (getting A) $$= \ \frac{2}{6} \ = \ \frac{1}{3} \ = \ 0.33$$

(ii) The total number of faces having D on it = 1

P (getting D) $$= \ \frac{1}{6} \ = \ 0.166$$