A child has a die whose six faces show the letters as given below:


The die is thrown once. What is the probability of getting

(i) A?

(ii) D?

The total number of possible outcomes (or events) = 6

\( P(E) \ = \ \frac{Number \ of \ favourable \ outcomes}{Total \ number \ of \ outcomes} \)

(i) The total number of faces having A on it = 2

P (getting A) \( = \ \frac{2}{6} \ = \ \frac{1}{3} \ = \ 0.33 \)

(ii) The total number of faces having D on it = 1

P (getting D) \( = \ \frac{1}{6} \ = \ 0.166 \)