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Answer :
(i) All the possible events are (H,H); (H,T); (T,H) and (T,T)
So, P (getting two heads) \( = \ \frac{1}{4} \)
and, P (getting one of the each) \( = \ \frac{2}{4} \ = \ \frac{1}{2} \)
\(\therefore \) This statement is incorrect.
(ii) Since the two outcomes are equally likely, this statement is correct.