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# Which of the following arguments are correct and which are not correct? Give reasons for your Solution: (i) If two coins are tossed simultaneously there are three possible outcomes—two heads, two tails or one of each. Therefore, for each of these outcomes, the probability is $$\frac{1}{3}$$ (ii) If a die is thrown, there are two possible outcomes—an odd number or an even number. Therefore, the probability of getting an odd number is $$\frac{1}{2}$$

(i) All the possible events are (H,H); (H,T); (T,H) and (T,T)

So, P (getting two heads) $$= \ \frac{1}{4}$$

and, P (getting one of the each) $$= \ \frac{2}{4} \ = \ \frac{1}{2}$$

$$\therefore$$ This statement is incorrect.

(ii) Since the two outcomes are equally likely, this statement is correct.