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Answer :
Since there are 5 days and both can go to the shop in 5 ways each so,
The total number of possible outcomes = 5 × 5 = 25
(i) The number of favourable events = 5 (Tue., Tue.), (Wed., Wed.), (Thu., Thu.), (Fri., Fri.), (Sat., Sat.)
So, P (both visiting on the same day) \(= \ \frac{5}{25} \ = \ \frac{1}{5} \)
(ii) The number of favourable events = 8 (Tue., Wed.), (Wed., Thu.), (Thu., Fri.), (Fri., Sat.), (Sat., Fri.), (Fri., Thu.), (Thu., Wed.), and (Wed., Tue.)
So, P(both visiting on the consecutive days) \( = \ \frac{8}{25} \)
(iii) P (both visiting on the different days) = 1 - P (both visiting on the same day)
So, P (both visiting on the different days) \( = \ 1 \ - \ \frac{1}{5} \ = \ \frac{4}{5} \)