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Answer :
The table will be as follows:
+ | 1 | 2 | 2 | 3 | 3 | 6 |
1 | 2 | 3 | 3 | 4 | 4 | 7 |
2 | 3 | 4 | 4 | 5 | 5 | 8 |
2 | 3 | 4 | 4 | 5 | 5 | 8 |
3 | 4 | 5 | 5 | 6 | 6 | 9 |
3 | 4 | 5 | 5 | 6 | 6 | 9 |
6 | 7 | 8 | 8 | 9 | 9 | 12 |
So, the total number of outcome = 6 × 6 = 36
(i) E (Even) = 18
P (Even) \( = \ \frac{18}{36} \ = \ \frac{1}{2} \)
(ii) E (sum is 6) = 4
P (sum is 6) \( = \ \frac{4}{36} \ = \ \frac{1}{9} \)
(iii) E (sum is atleast 6) = 15
P (sum is atleast 6) \( = \ \frac{15}{36} \ = \ \frac{5}{12} \)