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Answer :

It is given that the total number of red balls = 5

Let the total number of blue balls = x

So, the total no. of balls = x + 5

P(E) = \(\frac{(Number of favourable outcomes}{ Total number of outcomes} \)

P (drawing a blue ball) \( = \ \frac{x}{x \ + \ 5} \) ..... (i)

Similarly,

P (drawing a red ball) \( = \ \frac{5}{x \ + \ 5} \) ....(ii)

From equation (i) and (ii)

x = 10

So, the total number of blue balls = 10

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