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Answer :
From the question, it is clear that
Total volume of 3 rivers
= 3 × [(Surface area of a river) × Depth]
Given,
Surface area of a river
= [\( 1072 × \frac{75}{1000} \)] km
And,
Depth = \( \frac{3}{1000} \) km
Now, volume of 3 rivers
= 3 × [1072 × \( \frac{75}{1000} \)] × \( \frac{3}{1000} \)
= 0.72 km3
Now, volume of rainfall in one fortnight (14 days)
= total surface area × total height of rain
\( = \ 9780 \ × \ \frac{10}{100 \ × \ 1000} \)
= 9.7 km3
Volume of rainfall in 1 day
= \( \frac{9.7}{14} = 0.694 \ km^3 \)
For the total rainfall to be approximately equivalent to the addition to the normal water of three rivers, the volume of rainfall has to be equal to volume of 3 rivers.
Since 0.694 km3 is nearly equivalent to 0.72 km3,
We can say that the total rainfall was approximately equivalent to the addition to the normal water of the three rivers.