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Answer :

Given,

Diameter of upper circular end of frustum part = 18 cm

So, radius (r_{1}) = 9 cm

Now, the radius of the lower circular end of frustum (r_{2}) will be equal to the radius of the circular end of the cylinder

So, r_{2} = \(\frac{8}{2} \) = 4 cm

Now, height (h_{1}) of the frustum section = 22 - 10 = 12 cm

And,

Height (h_{2}) of cylindrical section = 10 cm (given)

Now, the slant height will be, \( l \ = \ \sqrt{(r_1 \ - \ r_2)^2 \ + \ (h_1)^2} \)

Or, l = 13 cm

Area of tin sheet required = CSA of frustum part + CSA of cylindrical part

\( = \ (r_1 \ + \ r_2)l \ + \ 2 \pi r_2 h_2 \)

Solving this we get,

Area of tin sheet required = 782 × \( \frac{4}{7} \) cm^{2}

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