10 mL of a solution of NaOH is found to be completely neutralised by 8 mL of a given solution of HCL. . If we take 20 mL of the same solution of NaOH, the amount of HCl solution (the same solution as before) required to neutralise it will be

- (a) 4 mL
- (b) 8 mL
- (c) 12 mL
- (d) 16 mL

Answer :

Since, 10 ml of NaOH requires 8 ml of HCl for neutralization,20 ml of NaOH will require:

(8 divided by 10)×20 = 16

Therefore,

Ans: (d) 16 ml

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- NCERT solutions for class 10 maths chapter 2 Polynomials
- NCERT solutions for class 10 maths chapter 3 Pair of linear equations in two variables
- NCERT solutions for class 10 maths chapter 4 Quadratic Equations
- NCERT solutions for class 10 maths chapter 5 Arithmetic Progressions
- NCERT solutions for class 10 maths chapter 6 Triangles
- NCERT solutions for class 10 maths chapter 7 Coordinate Geometry
- NCERT solutions for class 10 maths chapter 8 Introduction to Trigonometry
- NCERT solutions for class 10 maths chapter 9 Some Applications of Trigonometry
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- NCERT solutions for class 10 science chapter 2 Acids, Bases and Salts
- NCERT solutions for class 10 science chapter 3 Metals and Non Metals
- NCERT solutions for class 10 science chapter 4 Carbon and its Compounds
- NCERT solutions for class 10 science chapter 5 Periodic Classification of Elements
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- NCERT solutions for class 10 science chapter 15 Our Environment
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