How many 176 \(\Omega \) resistors (in parallel) are required to carry 5 A on a 220 V line?

For x number of resistors of resistance 176 \(\Omega \), the equivalent resistance of the resistors connected in parallel is given by Ohm's law as

V= IR R= \(\frac{V}{I} \) Where, Supply voltage, V= 220 V Current, I = 5 A Equivalent resistance of the combination = R,given as



Therefore, four resistors of 176 \(\Omega \) are required to draw the given amount of current.