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Answer :

Both the bulbs are connected in parallel. Therefore, potential difference across each of them will be 220 V, because no division of voltage occurs in a parallel circuit.

Current drawn by the bulb of rating 100 W is given by,Power = Voltage × Current

Current = \(\frac{Power}{Voltage} = \frac{60}{220} A \)

Hence, current drawn from the line

\( = \frac{100}{220} + \frac{60}{220} = 0.727 A \)

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