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Answer :

According to the given statement in the question:

=>\(y = 5x - 5\)............(1)

Three solutions of this equation can be written in a table as follows:

\(\begin{array} {|r|r|}\hline x & 0 & 1 & 2 \\ \hline y & -5 & 0 & 5 \\ \hline \end{array}\)

According to the given statement in the question:

=>\(y = 3x - 3\)............(2)

Three solutions of the equation (2) are :

\(\begin{array} {|r|r|}\hline x & 0 & 1 & 2 \\ \hline y & -3 & 0 & 3 \\ \hline \end{array}\)

Now the graph for the above equations (1) and (2) will be:

It can be observed that the required triangle is ABC.

The coordinates of its vertices are A (1, 0), B (0, –3), C (0, –5).

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- NCERT solutions for class 10 maths chapter 3 Pair of linear equations in two variables
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- NCERT solutions for class 10 maths chapter 5 Arithmetic Progressions
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- NCERT solutions for class 10 maths chapter 9 Some Applications of Trigonometry
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- NCERT solutions for class 10 maths chapter 14 Statistics
- NCERT solutions for class 10 maths chapter 15 Probability

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- NCERT solutions for class 10 science chapter 2 Acids, Bases and Salts
- NCERT solutions for class 10 science chapter 3 Metals and Non Metals
- NCERT solutions for class 10 science chapter 4 Carbon and its Compounds
- NCERT solutions for class 10 science chapter 5 Periodic Classification of Elements
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