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Answer :
According to the given statement in the question:
=>\(y = 5x - 5\)............(1)
Three solutions of this equation can be written in a table as follows:
\(\begin{array} {|r|r|}\hline x & 0 & 1 & 2 \\ \hline y & -5 & 0 & 5 \\ \hline \end{array}\)
According to the given statement in the question:
=>\(y = 3x - 3\)............(2)
Three solutions of the equation (2) are :
\(\begin{array} {|r|r|}\hline x & 0 & 1 & 2 \\ \hline y & -3 & 0 & 3 \\ \hline \end{array}\)
Now the graph for the above equations (1) and (2) will be:
It can be observed that the required triangle is ABC.
The coordinates of its vertices are A (1, 0), B (0, –3), C (0, –5).