Recall, \(\pi\) is defined as the ratio of the circumference (say c) of a circle to its diameter (say d).
That is, \(\pi = \frac{c}{d} \) . This seems to contradict the fact that \(\pi\) is irrational.
How will you resolve this contradiction?

Question

Recall, \(\pi\) is defined as the ratio of the circumference (say c) of a circle to its diameter (say d).
That is, \(\pi = \frac{c}{d} \) . This seems to contradict the fact that \(\pi\) is irrational.
How will you resolve this contradiction?

Accepted Answer

Answer :

First of all, there is not any contradiction. \(\pi\) defined here has an approximate value of \(\frac{22}{7} \) i.e. by comparing with \(\frac{c}{d} \) .

Also, any value measured on scale or physically is an approx value.

Recall, \(\pi\) is defined as the ratio of the circumference (say c) of a circle to its diameter (say d).
That is, \(\pi = \frac{c}{d} \) . This seems to contradict the fact that \(\pi\) is irrational.
How will you resolve this contradiction?

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Recall, \(\pi\) is defined as the ratio of the circumference (say c) of a circle to its diameter (say d). That is, \(\pi = \frac{c}{d} \) . This seems to contradict the fact that \(\pi\) is irrational. How will you resolve this contradiction?

NCERT solutions of related questions for Number Systems

NCERT solutions of related chapters class 9 maths

NCERT solutions of related chapters class 9 science

Recall, \(\pi\) is defined as the ratio of the circumference (say c) of a circle to its diameter (say d).
That is, \(\pi = \frac{c}{d} \) . This seems to contradict the fact that \(\pi\) is irrational.
How will you resolve this contradiction?