Premium Online Home Tutors
3 Tutor System
Starting just at 265/hour
Answer :
(i) we can get highest resistance by connecting the four coils in series.
Then, R = 4\(\Omega \) + 8\(\Omega \) + 12\(\Omega \) + 24\(\Omega \) = 48\(\Omega \)
(ii)We can get lowest resistance by connecting the four coils in parallel.
\(\frac{1}R=\frac{1}4 +\frac{1}8+\frac{1}{12} =\frac{12}{24}=\frac{1}2 \)
we get, R=2\(\Omega \)