Compute the heat generated while transferring 96000 coulomb of charge in one hour through a potential difference of 50 V.

Given, Potential difference (V) = 50V,
Charge (Q) = 96000 coulomb

Time, t = 1 hour = 60 X 60 s = 3600 s

Heat generated, H = VQ = 50Vx 96,000 C = 48,00,000 J = 4.8 x \(10^6\) J