An electric oven of 2 kW power rating is operated in a domestic electric circuit (220 V) that has a current rating of 5 A. What result do you expect ? Explain.

We have formula as P=VI
The electric oven draws a current given by

\(I=\frac{P}V=\frac{2kW}{220V}=\frac{2000}{220}=9.09A \)

Thus the electric oven draws much more than the current rating 5 A. thus, the circuit is overloaded so the fuse wire will blow and the circuit will break.