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Answer :
We have formula as P=VI
The electric oven draws a current given by
\(I=\frac{P}V=\frac{2kW}{220V}=\frac{2000}{220}=9.09A \)
Thus the electric oven draws much more than the current rating 5 A. thus, the circuit is overloaded so the fuse wire will blow and the circuit will break.