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3.Find :
i)\(2^{2/3} × 2^{1/5}\)
ii)\((1/{3^{3}})^7\)
iii)\({11^{1/2}}/11^{1/4}\)
iv)\(7^{1/2} × 8^{1/2}\)

Answer :

i)\(2^{2/3} × 2^{1/5}\) = \(2^{2/3 + 1/5}\) = \(2^{(10+3)/15}\) = \(2^{13/15}\)

ii)\((1/{3^{3}})^7\) = \(1/{3^{3 × 7}}\) = \(1/{3^{21}}\) = \(3^{-21}\)

iii)\({11^{1/2}}/11^{1/4}\) = \({11^{1/2}} × 11^{-1/4}\) = \(11^{(2-1)/4}\) = \(11^{1/4}\)

iv)\(7^{1/2} × 8^{1/2}\) = \({7 × 8}^{1/2}\) = \(56^{1/2}\)